Answer by glenn jackman for How to print specific duplicate line based on...
Use [ as the field delimiter, then split the last field on ,:awk -F '[[]'' {split($NF, f, /,/)} length(f) > max[$1] {line[$1] = $0; max[$1] = length(f)} END {for (l in line) print line[l]}'...
View ArticleAnswer by potong for How to print specific duplicate line based on fields number
This might work for you:sort -r file | sort -t, -k1,1 -u
View ArticleAnswer by Zsolt Botykai for How to print specific duplicate line based on...
Something like this might work:awk 'BEGIN {FS="["} Ff != gensub("^([^,]+).*","\\1","g",$0) { Ff = gensub("^([^,]+).*","\\1","g",$0) ; Lf = $NF ; if (length(Ml) > 0) { print Ml } } Ff ==...
View ArticleAnswer by kev for How to print specific duplicate line based on fields number
generate index file$ cat input.txt |sed 's/,\[/|[/g' | awk -F'|''{if(!gensub(/[[\])]/, "", "g", $NF))n=0;else n=split($NF, a, /,/); print NR,$1,n}' | sort -k2,2 -k3,3nr | awk '$2!=x{x=$2;print...
View ArticleHow to print specific duplicate line based on fields number
I need to print out only one of various consecutive lines with same first field, and the one must be the one with "more fields in its last field". That means that last field is a set of words, and I...
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